本文介绍了反序列化内部JSON对象的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我有一个类POJO
Class Pojo { String id; String name; //getter and setter }我有一个类似的json
I have a json like
{ "response" : [ { "id" : "1a", "name" : "foo" }, { "id" : "1b", "name" : "bar" } ] }我使用Jackson ObjectMapper进行反序列化。如何在不创建任何其他父类的情况下获得 List< Pojo> ?
I am using Jackson ObjectMapper for deserialization. How can I get List<Pojo> without creating any other parent class?
如果不可能,则是有可能获得 Pojo 对象,它只包含json字符串的第一个元素,即在这种情况下 id =1a和 name =foo?
If it is not possible, is it possible to get Pojo object which holds just first element of json string i.e. in this case id="1a" and name="foo"?
推荐答案您首先需要获取数组
String jsonStr = "{\"response\" : [ { \"id\" : \"1a\", \"name\" : \"foo\"},{ \"id\" : \"1b\",\"name\" : \"bar\" } ]}"; ObjectMapper mapper = new ObjectMapper(); JsonNode node = mapper.readTree(jsonStr); ArrayNode arrayNode = (ArrayNode) node.get("response"); System.out.println(arrayNode); List<Pojo> pojos = mapper.readValue(arrayNode.toString(), new TypeReference<List<Pojo>>() {}); System.out.println(pojos);打印(带 toString())
[{"id":"1a","name":"foo"},{"id":"1b","name":"bar"}] // the json array [id = 1a, name = foo, id = 1b, name = bar] // the list contents更多推荐
反序列化内部JSON对象
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