不确定如何对JSON对象jQuery/JavaScript进行排序

本文介绍了不确定如何对JSON对象jQuery/JavaScript进行排序的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！ 问题描述

示例字符串:

var output = { "myservices":[ {"name":"oozie", "hostidn": "1", "details":"failed process health monitor....", "currstatus":"Warning", "currstatusclass":"warning"}, {"name":"oozie", "hostidn": "2", "details":"failed process health monitor....", "currstatus":"Warning", "currstatusclass":"warning"}, {"name":"oozie", "hostidn": "3", "details":"failed process health monitor....", "currstatus":"Warning", "currstatusclass":"warning"}, {"name":"oozie", "hostidn": "4", "details":"failed process health monitor....", "currstatus":"Warning", "currstatusclass":"warning"}, {"name":"oozie", "hostidn": "5", "details":"failed process health monitor....", "currstatus":"Warning", "currstatusclass":"warning"}, {"name":"single-namenode", "hostidn": "2", "details":"failed process health monitor....", "currstatus":"Warning", "currstatusclass":"warning"} ]};

我的饼干杰克尝试这样做.

My Cracker Jack Attempt at doing it.

function sortJSONresultsByHost(a,b) { var objectIDA = parseInt(a.hostidn, 10) var objectIDB = parseInt(b.hostidn, 10) if(objectIDA === objectIDB) { return 0; } return objectIDA > objectIDB ? 1 : -1; } output.myservices.sort(sortJSONresultsByHost);

我实际上需要弄清楚如何对这种方式进行排序.如按hostidn，按名称，按currstatusclass.但是我不知道最好的方法.有没有一种方法可以使功能通过选择来执行，或者我需要根据我想做的功能来创建一组功能，如果可以的话?我上面的东西对我不起作用.

I actually need to figure out how to sort this various ways. Such as by hostidn, by name, by currstatusclass. But I can't figure out the best way to do it. Is there a way to make a function that could do any by choice or would I need to make a set of functions based on which i want to do, if either how? mine above is not working out for me.

推荐答案

function sortObjectsByKey(objects, key){ objects.sort(function() { return function(a, b){ var objectIDA = a[key]; var objectIDB = b[key]; if (objectIDA === objectIDB) { return 0; } return objectIDA > objectIDB ? 1 : -1; }; }()); } sortObjectsByKey(output.myservices, "hostidn"); console.log(output.myservices);