将Swift Closures作为值添加到Swift字典

本文介绍了将Swift Closures作为值添加到Swift字典的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！ 问题描述

我想创建一个Swift字典，它包含String类型作为其键和Closures作为其值。下面是我的代码，但它给我的错误：

'@ lvalue不等于'（String，（） - > Void）'

class CommandResolver { private var commandDict：[String：（） - >空虚]！ init（）{ self.setUpCommandDict（）; } func setUpCommandDict（）{ selfmandDict [OpenAssessment_1] = { println（I am inside inside closure）; } } }

看看关于StackOverflow关于字典中的闭包的其他问题，但它不给我任何满意的答案。

解决方案

如果你在 init 在调用你的设置函数之前，它应该工作：

class CommandResolver { private var commandDict： [String：（） - > Void] init（）{ commandDict = [：] setUpCommandDict（）} func setUpCommandDict（）{ commandDict [OpenAssessment_1] = { println（I am inside closure）} } } / pre>

I want to create a Swift dictionary that holds String type as its keys and Closures as its values. Following is the code that I have but it gives me the error:

'@lvalue is not identical to '(String, () -> Void)'

class CommandResolver { private var commandDict:[String : () -> Void]! init() { self.setUpCommandDict(); } func setUpCommandDict() { selfmandDict["OpenAssessment_1"] = { println("I am inside closure"); } } }

I tried looking at other question on StackOverflow regarding closures in dictionaries but it does not give me any satisfactory answer. So I would really appreciate some help here.

解决方案

If you initialize your dictionary in your init before calling your setup function, it should work:

class CommandResolver { private var commandDict: [String: () -> Void] init() { commandDict = [:] setUpCommandDict() } func setUpCommandDict() { commandDict["OpenAssessment_1"] = { println("I am inside closure") } } }