如何在Swift 4中使用Alamofire 4.7解析JSON

本文介绍了如何在Swift 4中使用Alamofire 4.7解析JSON的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！ 问题描述

我知道之前曾问过这个问题，但是答案是在Swift 3中使用的是旧版本的Alamofire。

I know this question was asked before, but answers were in Swift 3 and using older versions of Alamofire.

问题：可以吗？ t弄清楚如何从JSON响应中检索数据，主要是 api_key 。

Problem: Can't figure out how to retrieve data from JSON response, mainly api_key.

以下是我的响应代码：

Alamofire.request(serverLink!, headers: headers).responseJSON{ response in if response.value != nil { //Some code to get api_key print(response) } else { print("error") }

当我打印（响应）时，我得到以下信息：

When I print(response) I get the following:

SUCCESS: { user = { "api_key" = 9a13f31770b80767a57d753961acbd3a18eb1370; "created_on" = "2010-09-30T12:57:42Z"; firstname = Paul; id = 4; "last_login_on" = "2018-03-27T10:15:10+03:00"; lastname = Smith; login = admin; mail = "admin@demo"; status = 1; }; }

我需要得到的是

api_key = 9a13f31770b80767a57d753961acbd3a18eb1370;

"api_key" = 9a13f31770b80767a57d753961acbd3a18eb1370;

它可以是数组形式，dict或仅包含以下字符串：

It could be in form of array, dict or just string containing:

9a13f31770b807 ...

9a13f31770b807...

有人可以向我解释如何从此请求中获取（解码）吗？

Could someone please explain to me how to get(decode) it from this request?

编辑

print（response.result。值）：

RESPONSE: Optional({ user = { "api_key" = 9a13f31770b80767a57d753961acbd3a18eb1370; "created_on" = "2010-09-30T12:57:42Z"; firstname = Paul; id = 4; "last_login_on" = "2018-03-27T11:10:25+03:00"; lastname = Smith; login = admin; mail = "admin@demo"; status = 1; }; })

推荐答案

根据 docs ，这是访问序列化JSON响应的方式：

As per the docs, this is how you access the serialised JSON response:

if let json = response.result.value as? [String: Any] { print("JSON: \(json)") // serialized json response }

要访问 api_key ，您只需先打开成功字典和用户字典，然后就可以访问用户字典中的api_key属性

To access api_key you just need to unwrap the success and user dictionaries first and then you can access the api_key property in the user dictionary.

guard let user = json["user"] as? [String: Any], let apiKey = user["api_key"] as? String else { print("Failed to parse JSON") return } print(apiKey)