卷曲以返回 http 状态代码以及响应

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我使用 curl 来获取 http 标头以查找 http 状态代码并返回响应.我使用命令获取 http 标头

I use curl to get http headers to find http status code and also return response. I get the http headers with the command

curl -I localhost

为了得到响应，我使用命令

To get the response, I use the command

curl localhost

一旦使用了 -I 标志，我就只得到标头，而不再有响应.有没有办法在一个命令中同时获取 http 响应和标头/http 状态代码?

As soon as use the -I flag, I get only the headers and the response is no longer there. Is there a way to get both the http response and the headers/http status code in in one command?

推荐答案

我能够通过查看指定使用 - 作为输出的 curl 文档来获得解决方案标准输出.

I was able to get a solution by looking at the curl doc which specifies to use - for the output to get the output to stdout.

curl -o - localhost

要获得仅包含 http 返回码的响应，我可以这样做

To get the response with just the http return code, I could just do

curl -o /dev/null -s -w "%{http_code} " localhost