卷曲以返回http状态代码以及响应

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我使用curl获取HTTP标头，以查找http状态代码并返回响应。我使用以下命令获取http标头

I use curl to get http headers to find http status code and also return response. I get the http headers with the command

curl -I localhost

要获得响应，我使用命令

To get the response, I use the command

curl localhost

一旦使用-I标志，我只会得到标头，并且响应不再存在。有没有办法在一个命令中同时获取http响应和标头/ http状态代码？

As soon as use the -I flag, I get only the headers and the response is no longer there. Is there a way to get both the http response and the headers/http status code in in one command?

推荐答案

通过查看curl文档获得解决方案，该文档指定使用-作为输出以将输出输出到stdout。

I was able to get a solution by looking at the curl doc which specifies to use - for the output to get the output to stdout.

curl -o - localhost

获取响应仅使用http返回代码，我就可以

To get the response with just the http return code, I could just do

curl -o /dev/null -s -w "%{http_code}\n" localhost