我们正在考虑使用 Akka-HTTP Java API - 使用路由 DSL.
We are looking at using Akka-HTTP Java API - using Routing DSL.
不清楚如何使用路由功能来响应一个HttpRequest;使用无类型 Akka Actor.例如,匹配 Route 路径后,我们如何将请求传递给处理程序"ActorRef,然后以异步方式响应 HttpResponse?
It's not clear how to use the Routing functionality to respond to an HttpRequest; using an Untyped Akka Actor. For example, upon matching a Route path, how do we hand off the request to a "handler" ActorRef, which will then respond with a HttpResponse in a asynchronous way?
Akka-User 邮件列表上发布了一个类似的问题,但没有后续解决方案 - groups.google/d/msg/akka-user/qHe3Ko7EVvg/KC-aKz_o5aoJ.
A similar question was posted on Akka-User mailing list, but with no followup solutions as such - groups.google/d/msg/akka-user/qHe3Ko7EVvg/KC-aKz_o5aoJ.
推荐答案这可以通过 onComplete 指令和 ask 模式.
在下面的示例中,RequestHandlerActor 角色用于基于 HttpRequest 创建一个 HttpResponse.从路由内询问此 Actor.
In the below example the RequestHandlerActor actor is used to create a HttpResponse based on the HttpRequest. This Actor is asked from within the route.
我从未使用 Java 来路由代码,所以我的回答是在 Scala 中.
I have never used Java for routing code so my response is in Scala.
import scala.concurrent.duration._ import akka.actor.ActorSystem import akka.http.scaladsl.model.HttpResponse import akka.http.scaladsl.model.HttpRequest import akka.actor.Actor import akka.http.scaladsl.server.Directives._ import akka.actor.Props import akka.pattern.ask import akka.util.Timeout import scala.util.{Success, Failure} import akka.http.scaladsl.model.StatusCodes.InternalServerError class RequestHandlerActor extends Actor { override def receive = { case httpRequest : HttpRequest => sender() ! HttpResponse(entity = "actor responds nicely") } } implicit val actorSystem = ActorSystem() implicit val timeout = Timeout(5 seconds) val requestRef = actorSystem actorOf Props[RequestHandlerActor] val route = extractRequest { request => onComplete((requestRef ? request).mapTo[HttpResponse]) { case Success(response) => complete(response) case Failure(ex) => complete((InternalServerError, s"Actor not playing nice: ${ex.getMessage}")) } }然后可以使用此路由传递到bindAndHandle 方法与任何其他 Flow 一样.
This route can then be used passed into the bindAndHandle method like any other Flow.
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