我有一个带有多个子SKSpriteNodes的SKNode。一个简单的例子:
I have an SKNode with a number of child SKSpriteNodes. A simplified example:
var parentNode = SKNode() var childNode1 = SKSpriteNode() var childNode2 = SKSpriteNode() self.addChild(parentNode) parentNode.addChild(childNode1) parentNode.addChild(childNode2)我想对所有这些孩子运行 colorizeWithColor 操作。当我在 parentNode 上运行操作时,没有任何效果。
I want to run a colorizeWithColor action on all of these children. When I run the action on parentNode, there's no effect.
我不能使用 enumerateChildNodesWithName 在父项上,因为它的许多子项已经有我正在使用的名称。
I can't use enumerateChildNodesWithName on the parent, because many of its children already have names I'm using.
有没有办法循环所有子项 parentNode ,为了对所有这些操作执行单个操作?
Is there a way of looping through all children of parentNode, in order to run a single action on all of them?
推荐答案您可以简单地枚举 parentNode.children :
for child in parentNode.children as! [SKNode] { // ... }如有必要,检查每个孩子是否实际上是 SKSpriteNode :
If necessary, check each child if it is actually a SKSpriteNode:
for child in parentNode.children { if let spriteNode = child as? SKSpriteNode { // ... } }从 Swift 2(Xcode 7)开始,枚举和可选的强制转换可以与带有案例模式的for循环结合使用:
As of Swift 2 (Xcode 7), enumeration and optional cast can be combined with to a for-loop with a case-pattern:
for case let child as SKSpriteNode in parentNode.children { // ... }更多推荐
循环遍历SKNode的所有孩子?
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