Angular:如何获取路由器出口的组件实例

本文介绍了Angular:如何获取路由器出口的组件实例的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！ 问题描述

html:

<router-outlet></router-outlet>

组件:

@Component({ selector: 'xx', templateUrl: './xx.html', styleUrls: ['./xx.css'], providers: [ RouterOutlet] }) export class AppComponent { constructor(private routeroutlet: RouterOutlet){ } getref() { console.log(this.routeroutlet); console.log('refresh', this.routeroutletponent); } }

我遇到此错误

core.es5.js:1224 ERROR Error: Outlet is not activated at RouterOutlet.get [as component] (router.es5.js:5449) at AppComponent.onRefreshscrum (appponent.ts:343) at Object.eval [as handleEvent] (AppComponent.ngfactory.js:111) at Object.handleEvent (core.es5.js:12251) at Object.handleEvent (core.es5.js:12975) at dispatchEvent (core.es5.js:8863) at eval (core.es5.js:11025) at SafeSubscriber.schedulerFn [as _next] (core.es5.js:3851) at SafeSubscriber.__tryOrUnsub (Subscriber.js:223) at SafeSubscriber.next (Subscriber.js:172)

控制台结果:(this.routeroutlet)

console result:(this.routeroutlet)

RouterOutlet { parentContexts: ChildrenOutletContexts, location: null, resolver: CodegenComponentFactoryResolver, changeDetector: ViewRef_, activated: null, …}activateEvents: EventEmitter {_isScalar: false, observers: Array(0), closed: false, isStopped: false, hasError: false,  …} closed: false hasError: false isStopped: false observers: []thrown Error: null __isAsync: false _isScalar: false __proto__: Subject activated: null activatedRoute: (...)activatedRouteData: (...)changeDetector: ViewRef_ {_view: {…}, _viewContainerRef: null, _appRef: null} component: [Exception: Error: Outlet is not activated at RouterOutlet.get [as component] (webpack:///./~/@angular/router/@angular/router.es5.js?:5449:23) at RouterOutlet.remoteFunction (<anonymous>:2:26)]deactivateEvents: EventEmitter {_isScalar: false, observers: Array(0), closed: false, isStopped: false, hasError: false, …} isActivated: (...)location: nulllocationFactoryResolver: (...)l ocationInjector: (...)name: "primary" parentContexts: ChildrenOutletContexts {contexts: Map(1)}resolver: CodegenComponentFactoryResolver {_parent: null, _ngModule: NgModuleRef_, _factories: Map(52)}_activatedRoute: null__proto__: ObjectactivateWith: ƒ (activatedRoute, resolver)activatedRoute: (...)activatedRouteData: (...)attach: ƒ (ref, activatedRoute)component: (...)deactivate: ƒ ()detach: ƒ ()isActivated: (...)locationFactoryResolver: (...)locationInjector: (...)ngOnDestroy: ƒ ()ngOnInit: ƒ ()arguments: (...)caller: (...)length: 0name: ""prototype: {constructor: ƒ}__proto__: ƒ ()[[FunctionLocation]]: router.es5.js:5400[[Scopes]]: Scopes[3]constructor: ƒ RouterOutlet(parentContexts, location, resolver, name, changeDetector)get activatedRoute: ƒ ()get activatedRouteData: ƒ ()get component: ƒ ()get isActivated: ƒ ()get locationFactoryResolver: ƒ ()get locationInjector: ƒ ()__proto__: Object

上面的控制台结果是用于控制routeroutlet obj.

The above console result is for console the routeroutlet obj.

我想访问在路由器出口呈现的组件的实例.我如何访问该组件的实例?

I want to access the instance of the component which is rendered in router-outlet. how i access the instance of the component?

推荐答案

不要尝试将RouterOutlet用作提供程序.而是将(activate)属性添加到路由器出口标签中，如下所示:

Don't try to use RouterOutlet as a provider. Instead add the (activate) attribute to your router-outlet tag like this:

<router-outlet (activate)="onRouterOutletActivate($event)"></router-outlet>

然后在包含router-outlet元素的组件(您的AppComponent类)中，应实现onRouterActivate方法:

And then in the component containing the router-outlet element (your AppComponent class) you should implement the onRouterActivate method:

public onRouterOutletActivate(event : any) { console.log(event); }

，它将在事件参数中为您提供路由组件实例，在此示例中，该参数已写入Web控制台.

which will give you the route component instance in the event parameter, in this example written to the web console.