SQL查询以获取主管层次结构列表。员工

本文介绍了SQL查询以获取主管层次结构列表。员工->主管->主管的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！ 问题描述

我有两个表Employee和Department这幅图显示了每个员工的经理。我想编写一个SQL查询，为我提供所有主管（经理，经理的经理..）的列表。

I have two tables Employee and Department this image shows the manager of every employee. I want to write a SQL query that gives me a list of all the supervisor (Manager, Manager of Manager..).

我只希望显示一列授予特定雇员时的主管名单。

I just want a single column that displays a list of supervisor when given a particular employee.

例如如果我给员工id = 202，那么我应该收到200,130

E.g. If I give employee id = 202 then I should receive 200,130

|supervisor | +-----------+ | 200 | | 130 |

我有此查询

WITH emp_dept as( SELECT employee_id,manager_id FROM employee,department WHERE employee.dept_id= department.dept_id ) WITH recursive p as ( select e1.employee_id, e1.manager_id from emp_dept e1 where employee_id = 202 union all select e2.employee_id , e2.manager_id from p join emp_dept e2 ON e2.employee_id = p.manager_id ) select manager_id from p

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能够使用它。我正在使用pgadmin4。

I am not able to use it. I am using pgadmin4.

如果有人可以帮助我进行此查询，我将不胜感激

If anyone could help me with this query I would greatly appreciate it

推荐答案

这是我问题的解决方案

with recursive p as ( WITH emp_dept as( SELECT employee_id,manager_id FROM employee,department WHERE employee.dept_id= department.dept_id ) select e1.employee_id, e1.manager_id from emp_dept e1 where e1.employee_id = 202 union select e2.employee_id , e2.manager_id from p join emp_dept e2 ON e2.employee_id = p.manager_id ) select manager_id from p