我要显示在列表视图我一个非常简单的分隔符。我做了一个扩展SimpleAdapter自定义适配器,我的工作的实施有点。它显示了分频器和我的名单正确的,但一旦我开始滚动,然后滚动备份分频器被搞砸了,放在代替时listItems等有时当我滚动多一些它看起来正确的一次。这是我的code为'getView
I want to display a very simple separator in my listview. I have made a custom adapter that extends 'SimpleAdapter' and my implementation works somewhat. It displays the dividers and my list correct but once I start to scroll and then scroll back up the dividers gets messed up, placed instead of listitems etc. Sometime when I scroll some more it will look correct again. This is my code for 'getView'
@Override public View getView(int position, View convertView, ViewGroup parent){ if(((String)items.get(position).get("name")).startsWith("-")){ View divider = inflater.inflate(R.layout.list_separator, null); TextView separator = (TextView)divider.findViewById(R.id.separator); separator.setText(((String)items.get(position).get("name"))); return divider; } else { return super.getView(position, convertView, parent); } }什么可能是我的问题?
What might be my problem?
推荐答案如果您的分隔符是很简单的,你说,你有两个更好的方法来把它的列表视图:
If your separator is very simple as you say, you have two better ways to put it in the listview:
采用了android 1.Put它在XML:分属性:
1.Put it in the xml using android:divider attribute:
<item name="android:divider">@layout/list_separator</item>2.使用方法 setDivider()从ListView控件,给你的布局绘制对象:
2.Use the method setDivider() from ListView, give your layout as Drawable.:
ListView lv = ... ; lv.setDivider(getResources().getDrawable(R.layout.list_separator));更多推荐
Android的ListView的分离器
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