Apache HTTP客户端，POST请求.如何正确设置请求参数?

本文介绍了Apache HTTP客户端，POST请求.如何正确设置请求参数?的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！ 问题描述

我正在使用Apache HTTP Client，需要将POST请求发送到我的servlet. 发送请求时，我的servlet没有收到任何参数(在HttpServletRequest中).

I'm using Apache HTTP Client and I need to send a POST request to my servlet. When the request is sent my servlet does not receive any parameters (in the HttpServletRequest).

这是客户端程序代码:

// Engage the HTTP client DefaultHttpClient httpclient = new DefaultHttpClient(); HttpResponse response; try { HttpPost httpPost = new HttpPost("localhost:8080/test-json-web/JSONReceiverServlet"); // Setup the request parameters HttpParams params = new BasicHttpParams(); params.setParameter("taskdef", task1JsonString); httpPost.setParams(params); // Make the request response = httpclient.execute(httpPost); HttpEntity responseEntity = response.getEntity(); System.out.println("----------------------------------------"); System.out.println(response.getStatusLine()); if(responseEntity != null) { System.out.println("Response content length: " + responseEntity.getContentLength()); } String jsonResultString = EntityUtils.toString(responseEntity); EntityUtils.consume(responseEntity); System.out.println("----------------------------------------"); System.out.println("result:"); System.out.println(); } catch (ClientProtocolException e) { e.printStackTrace(); } catch (IOException e) { e.printStackTrace(); } finally { httpclient.getConnectionManager().shutdown(); }

如何正确设置POST请求参数，以便servlet实际接收它们?

How to correctly set POST request parameters so that servlet actually receives them?

推荐答案

尝试一下:

List <NameValuePair> nvps = new ArrayList <NameValuePair>(); nvps.add(new BasicNameValuePair("IDToken1", "username")); nvps.add(new BasicNameValuePair("IDToken2", "password")); httPost.setEntity(new UrlEncodedFormEntity(nvps, Consts.UTF_8));