jQuery AJAX或XHR请求触发来自完成回调的失败回调

本文介绍了jQuery AJAX或XHR请求触发来自完成回调的失败回调的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！ 问题描述

在我完成的jQuery XHR处理程序(通过$ .get()调用创建)中是否存在一种方法来查找响应中的问题，然后使用自定义触发已注册的后续处理程序(总是失败&总是)错误消息?

Is there a way in my done handler of a jQuery XHR (created from a $.get() call) to look for problems in the response and then trigger the registered subsequent handlers (lie fail & always) with a custom error message?

类似这样的东西:

$.get( URL ) .done( function (data, status, res) { if(/*some condition*/){ this.Reject(res, status, "some reason"); return } //Do stuff on success } ) .fail( //Common error handler here ) .always( //common always handler here );

完成第二个过滤器的种类.原因当然是所有在200个响应中都出现错误的API，而jQuery永远不会知道这是一个错误.

Kind of a secondary filter on done. The reason is of course all the APIs that shove an error in a 200 response that jQuery could never know was an error.

推荐答案

我想出了如何做到这一点，并且效果很好:

I figured out how to do this, and it works nicely:

$.get( URL ) .then( function (data, status, res) { if(/**some error check**/({ return $.Deferred().reject(res, status, "error message"); } return $.Deferred().resolve(data, status, res); } ) .done( function (data, status, res) { //Do stuff on success } ) .fail( //Common error handler here ) .always( //common always handler here );

就像一个魅力一样工作，现在我完成的工作中没有混乱的数据错误处理，我可以专注于处理数据或设置错误消息.

works like a charm, now i don't have messy data error handling in my done, i can just focus on processing data or setting error messages.