本文介绍了Java消息传递服务示例的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我是JMS的新手.但是我对JMS有很好的了解.我的问题是,即使是一个简单的jms示例,我也无法运行. 我在执行以下代码时得到"javax.naming.NoInitialContextException:需要在环境或系统属性中指定类名称"
I''m new to JMS. but i have good knowledge of JMS. my problem is, I''m not able to run even a simple jms example. I''m getting "javax.naming.NoInitialContextException: Need to specify class name in environment or system property" when i execute the following code
Context con = new InitialContext(); Car car = new Car(); con.bind("car",car); Object lookup = con.lookup("car");帮助我解决这个问题.我整天都在尝试tis. 在此先感谢
help me out to sesolve tis problem. i have been trying tis for the whole day. Thanks in Advance
推荐答案[ ^ ],可能的原因是您的配置中缺少定义. This hints[^] that a likely cause is a missing definition on your config.
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Java消息传递服务示例
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