我如何从request.FILES获取文件名？

本文介绍了我如何从request.FILES获取文件名？的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！ 问题描述

如何从Django中的request.FILES获取文件名？

How can I get the file name from request.FILES in Django?

def upload(request): if request.method == 'POST': form = UploadForm(request.POST, request.FILES) if form.is_valid(): upload = Upload() upload.timestamp = datetime.datetime.now() save_instance(form, upload)

我尝试使用这个但没有起作用：

I tried using this but it did not work:

if 'filename' in request.FILES: filename = request.FILES['filename']

推荐答案

request.FILES['filename'].name

从 请求 文档。

如果您不知道密钥，可以遍历文件：

If you don't know the key, you can iterate over the files:

for filename, file in request.FILES.iteritems(): name = request.FILES[filename].name