我尝试添加 set follow-fork-模式孩子如下所示: unix.derkeiler/Newsgroups/comp.unix.programmer/2006-02/msg00435.html
1 。如何调试(0 == pid)?
2。当我到等待语句时,调试器刚刚返回,不等待()假设挂起,直到孩子返回?为什么会立即返回?
解决方案您的问题可能是由于detach-on-fork关闭DSF默认设置(也是gdb的默认值)。
1)将断点放在execlp ...和returnedpid = ...的行上。 2)在调试配置中启用不间断模式和自动调试分叉进程。 3)启动调试会话。您将在小孩或父母中点击一个断点。现在看看调试视图。
你会注意到你的二进制显示两个线程。
4)点击一个或另一个(上图中带有main()的行)来切换调试上下文。
I'm trying to debug some fork() mechanism with eclipse cdt (Juno). I wrote the program in C.
if( -1 == (pid = fork()) ) /* error */ goto cleanup; else if ( 0 == pid ) /* child */ { execlp("gcc", "gcc", cFilePath, "-o" , GCC_OUTPUT_FILE_NAME, NULL); goto cleanup; /* Arrives here only on error! */ } else if (pid > 0) /* parent - checks: correct pid returns, returns normally, with exit status = 0*/ { returnedpid = wait(exitStatus); if( pid != returnedpid || exitStatus == NULL || !WIFEXITED(*exitStatus) || !WEXITSTATUS(*exitStatus) ) goto cleanup; }I tried to add "set follow-fork-mode child" as said here: unix.derkeiler/Newsgroups/comp.unix.programmer/2006-02/msg00435.html
1. How can I debug the code section where (0==pid)?
2. When I get to the wait statement, the debugger just return immediately, isn't wait() suppose to suspend till the child returns? Why is it return immediately?
解决方案Your problems are probably due to "detach-on-fork" being set to off. DSF sets this by default (it's also gdb's default).
1) Put a breakpoint onto lines with "execlp..." and "returnedpid =...". 2) In debug configuration enable "non-stop mode" and "automatically debug forked process". 3) Start debug session. You will hit a breakpoint either in child or parent. Now see debug view.
You will notice your binary shows two threads.
4) Click on one or the other (lines with main() in above image) to switch debug context.
更多推荐
调试fork()在eclipse cdt
发布评论