IOError: [Errno 32] 管道破裂:`prog.py

本文介绍了IOError: [Errno 32] 管道破裂:`prog.py |其他命令`的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！ 问题描述

我有一个非常简单的 Python 3 脚本:

I have a very simple Python 3 script:

f1 = open('a.txt', 'r') print(f1.readlines()) f2 = open('b.txt', 'r') print(f2.readlines()) f3 = open('c.txt', 'r') print(f3.readlines()) f4 = open('d.txt', 'r') print(f4.readlines()) f1.close() f2.close() f3.close() f4.close()

但它总是说:

IOError: [Errno 32] Broken pipe

我在网上看到了各种复杂的解决方法，但是我直接复制了这段代码，所以我认为是代码有问题，而不是Python的SIGPIPE.

I saw on the internet all the complicated ways to fix this, but I copied this code directly, so I think that there is something wrong with the code and not Python's SIGPIPE.

我正在重定向输出，所以如果上面的脚本被命名为open.py"，那么我要运行的命令是:

I am redirecting the output, so if the above script was named "open.py", then my command to run would be:

open.py | othercommand

推荐答案

我没有复现这个问题，但也许这个方法可以解决它:(将一行一行写入 stdout 而不是使用打印)

I haven't reproduced the issue, but perhaps this method would solve it: (writing line by line to stdout rather than using print)

import sys with open('a.txt', 'r') as f1: for line in f1: sys.stdout.write(line)

你能抓住断掉的管道吗?这将文件逐行写入 stdout 直到管道关闭.

import sys, errno try: with open('a.txt', 'r') as f1: for line in f1: sys.stdout.write(line) except IOError as e: if e.errno == errno.EPIPE: # Handle error

您还需要确保 othercommand 在管道变得太大之前从管道中读取 - unix.stackexchange/questions/11946/how-big-is-the-pipe-buffer

You also need to make sure that othercommand is reading from the pipe before it gets too big - unix.stackexchange/questions/11946/how-big-is-the-pipe-buffer