我正在Windows 7 64位系统上运行WAMP。 PATH 变量设置为 c:\wamp\bin\php\php5.3.13\
I'm running WAMP on Windows 7 64 Bits. The PATH variable is set to c:\wamp\bin\php\php5.3.13\
我正在尝试安装Symfony,但我不明白为什么先行运行而不是第二行:
I'm trying to install Symfony and I do not understand why first line runs and not the second:
运行成功:
php c:\wamp\bin\php\php5.3.13\composer.phar update此行失败:
This line fails:
php composer.phar update有错误:
无法打开输入文件:composer.phar
"Could not open input file: composer.phar"
什么可以解释这个吗?
get_include_path 返回:`
get_include_path returns : `
.; C:wamp\bin\php\php5.3.13\php\PEAR`。
.;C:\wamp\bin\php\php5.3.13\php\PEAR`.
这是否意味着如果composer.phar不在PEAR目录中,则 php composer.phar update将不起作用?
Does this mean that if composer.phar is not in PEAR directory 'php composer.phar update' will not work?
推荐答案您应该尝试此安装ead:
You should try this instead:
composer.phar更新
composer.phar update
为什么PHP会意识到您的$ PATH变量?
Why would php be aware of your $PATH variable?
另外,我认为$ PATH仅在处理命令行的第一个单词时由您的Shell使用。
Plus, I think $PATH is only used by your shell when dealing with the first word of your command line.
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php composer.phar更新不适用于Symfony安装
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