本文介绍了如何使用Jersey客户端POST方法提交数据的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我是泽西的新手。我需要实现Jersey客户端以POST方法提交数据。 curl命令是:
I am new to Jersey. I need to implement a Jersey client to submit data with POST method. The curl command is:
curl -d '{"switch": "00:00:00:00:00:00:00:01", "name":"flow-mod-1", "priority":"32768", "ingress-port":"1","active":"true", "actions":"output=2"}' localhost:8080/wm/staticflowentrypusher/json所以我想弄清楚如何使用Jersey客户端来实现上面的curl命令。
So I am trying to figure out how to use Jersey client to implement the above curl command.
到目前为止我已经完成了:
So far I have done:
public class FLClient { private static Client client; private static WebResource webResource; private static String baseuri = "localhost:8080/wm/staticflowentrypusher/json"; private static ClientResponse response; private static String output = null; public static void main(String[] args) { try { client = Client.create(); webResource = client.resource(baseuri); // implement POST data } catch (Exception e) { e.printStackTrace(); } } }有人可以帮助我吗?
推荐答案现在我弄清楚了。这是我的解决方案:
Now I figure it out. Here is my solution:
public static void main(String[] args) { try { Client client = Client.create(); WebResource webResource = client.resource(baseuri); String input = "{\"switch\": \"00:00:00:00:00:00:00:01\", " + "\"name\":\"flow-mod-1\", \"priority\":\"32768\", " + "\"ingress-port\":\"1\",\"active\":\"true\", " + "\"actions\":\"output=2\"}"; // POST method ClientResponse response = webResource.accept("application/json") .type("application/json").post(ClientResponse.class, input); // check response status code if (response.getStatus() != 200) { throw new RuntimeException("Failed : HTTP error code : " + response.getStatus()); } // display response String output = response.getEntity(String.class); System.out.println("Output from Server .... "); System.out.println(output + "\n"); } catch (Exception e) { e.printStackTrace(); } }更多推荐
如何使用Jersey客户端POST方法提交数据
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