跳过迭代器

本文介绍了跳过迭代器的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！ 问题描述

我有我想传递给一个函数值序列，需要一个（迭代器开始，结束迭代器）对。不过，我只希望要处理原来的顺序每隔第二个元素。

I have a sequence of values that I'd like to pass to a function that takes a (iterator begin, iterator end) pair. However, I only want every second element in the original sequence to be processed.

有没有使用标准 - 库/升压创建一个迭代器的外观，让我原来的顺序传递一个很好的方式？我想简单的东西像这样应该已经在升压或迭代器范围内库，但我没有发现任何东西。

Is there a nice way using Standard-Lib/Boost to create an iterator facade that will allow me to pass in the original sequence? I figured something simple like this would already be in the boost iterators or range libraries, but I didn't find anything.

还是我失去了另一种完全明显的方式做到这一点？当然，我知道我一直都复制值到另一个序列的选择，但是这不是我想做的事情。

Or am I missing another completely obvious way to do this? Of course, I know I always have the option of copying the values to another sequence, but that's not what I want to do.

编辑：我知道 filter_iterator ，但过滤价值观 - 它不会改变的方式迭代进步

I know about filter_iterator, but that filters on values - it doesn't change the way the iteration advances.

推荐答案

我想你想的的boost ::适配器::跨入