特定日期的Cron表达式

本文介绍了特定日期的Cron表达式的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！ 问题描述

我想要一个代表2010年9月6日的cron表达6:00 am

I want a cron expression that represents 6th September 2010 6:00 am

推荐答案

原始问题标记为 cron 所以这第一部分适用于此。有关Quartz CronTrigger工具的更新答案，请参见下文。

Original question was tagged cron so this first section applies to that. See below for an updated answer for the Quartz CronTrigger tool.

大多数crontab不允许您指定年份可能不得不将它放在脚本本身（或脚本/程序周围的包装）中。

Most crontabs don't let you specify the year so you'll probably have to put that in the script itself (or a wrapper around the script/program).

你可以这样做：

if [[ $(date +%Y) != 2010 ]] ; then exit fi

您要查找的选项9月6日上午6点每个年份是

The option you're looking for to run at 6am on September 6 every year is

0 6 6 9 * your_command_goes_here | | | | | | | | | +- any day of the week. | | | +--- 9th month (September). | | +----- 6th day of the month. | +------- 6th hour of the day. +--------- Top of the hour (minutes = 0).

对于Quartz CronTrigger格式，你会看起来像：

For the Quartz CronTrigger format, you'd be looking at something like:

0 0 6 6 9 ? 2010 | | | | | | | | | | | | | +- 2010 only. | | | | | +----- any day of the week. | | | | +------- 9th month (September). | | | +--------- 6th day of the month. | | +----------- 6th hour of the day. | +------------- Top of the hour (minutes = 0). +--------------- Top of the minute (seconds = 0).

（从 here ）。