我已经搜索了一些问题,例如 docker ENV vs RUN export ,它解释了这些命令之间的差异,但无助于解决我的问题.
I've search some of the questions already like docker ENV vs RUN export, which explains differences between those commands, but didn't help in solving my problem.
例如,我有一个名为 myscript 的脚本:
For example I have a script called myscript:
#!/bin/bash export PLATFORM_HOME="$(pwd)"在Dockerfile中有以下几行:
And have following lines in Dockerfile:
... COPY myscript.sh / RUN ./myscript.sh我还试图在调用脚本之前使用ENTRYPOINT而不是RUN或声明变量,所有这些都没有成功.
I've also tried to use ENTRYPOINT instead of RUN or declaring variable before calling the script, all that with no success.
我要实现的是,可以从使用该代码作为基础的其他Dockerfile中引用 PLATFORM_HOME .怎么做?
What I want to achieve is that PLATFORM_HOME can be referenced from other Dockerfiles which use that one as a base. How to do it ?
推荐答案无法将变量从脚本导出到子图像.通常,环境变量向下传播,从不向上传播.
There's no way to export a variable from a script to a child image. As a general rule, environment variables travel down, never up to a parent.
ENV 将保留在构建中环境以及子图像和容器.
ENV will persist in the build environment and to child images and containers.
Dockerfile
FROM busybox ENV PLATFORM_HOME test RUN echo $PLATFORM_HOMEDockerfile.child
FROM me/platform RUN echo $PLATFORM_HOME CMD ["sh", "-c", "echo $PLATFORM_HOME"]建立父母
docker build -t me/platform .然后建立孩子:
→ docker build -f Dockerfile.child -t me/platform-test . Sending build context to Docker daemon 3.072kB Step 1/3 : FROM me/platform ---> 539b52190af4 Step 2/3 : RUN echo $PLATFORM_HOME ---> Using cache ---> 40e0bfa872ed Step 3/3 : CMD sh -c echo $PLATFORM_HOME ---> Using cache ---> 0c0e842f99fd Successfully built 0c0e842f99fd Successfully tagged me/platform-test:latest然后运行
→ docker run --rm me/platform-test test更多推荐
docker运行脚本,导出环境变量
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