创建一个在gradle中的所有其他任务之前运行的任务

本文介绍了创建一个在gradle中的所有其他任务之前运行的任务的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！ 问题描述

我需要创建一个初始化任务，该任务在执行时将在所有其他任务之前运行.

I need to create an initialize task that will run before all other task when I execute it.

task A { println "Task A" } task initializer { println "initialized" }

如果我执行gradle -q A，输出将是:

If I execute gradle -q A, the output will be:

>initialized >Task A

现在，如果我要添加:

task B { println "Task B" }

执行gradle -q B，我得到:

>initialized >Task B

所以我执行哪个任务都没有关系，它总是首先被初始化".

So it doesn't matter which task I execute, it always get "initialized" first.

推荐答案

您可以使每个名称不是"initializer"的Task都依赖于"initializer"任务.例如:

You can make every Task who's name is NOT 'initializer' depend on the 'initializer' task. Eg:

task initializer { doLast { println "initializer" } } task task1() { doLast { println "task1" } } // make every other task depend on 'initializer' // matching() and all() are "live" so any tasks declared after this line will also depend on 'initializer' tasks.matching { it.name != 'initializer' }.all { Task task -> task.dependsOn initializer } task task2() { doLast { println "task2" } }

或者您可以添加 BuildListener (或使用一个便利方法，例如: Gradle.buildStarted(...))

Or you could add a BuildListener (or use one of the convenience methods eg: Gradle.buildStarted(...))