本文介绍了如何解析不带引号的JSON字符串的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我有一个JSON字符串,其中没有引用键和值,我想将其转换为格式正确的JSON。
I have a JSON string where neither the keys nor the values are quoted and I would like to transform it to a correctly formatted JSON.
{basic:{0:{index:0, license:t, nameSID:n, image:"img_left", descriptionSID:t, category:r}}是否有可以处理它的Java库?我试过杰克逊但它不起作用。
Is there a Java library that could handle it? I tried Jackson but it does not work.
问候, Jan
regards, Jan
推荐答案您可以使用 JsonParser.Feature.ALLOW_UNQUOTED_FIELD_NAMES 与杰克逊允许不带引号的字段名称:
You can use JsonParser.Feature.ALLOW_UNQUOTED_FIELD_NAMES with Jackson to allow unquoted field names:
JsonFactory factory = new JsonFactory(); factory.configure(JsonParser.Feature.ALLOW_UNQUOTED_FIELD_NAMES, true); JsonParser jp = factory.createJsonParser(new FileInputStream("content.json"));更多推荐
如何解析不带引号的JSON字符串
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