通过“运行"将CLI参数传递给可执行文件

本文介绍了通过“运行"将CLI参数传递给可执行文件的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！ 问题描述

我有一个程序 readfile.go ，我想将命令行参数 os.Args [1] 也作为 readfile.go .

I have a program readfile.go and I want to give the command line argument os.Args[1] also as readfile.go.

但是，运行"认为它是自身的一个附加参数，而不是输出可执行文件.是否有一个标志可以告诉'go run'这是可执行文件的参数?

However 'go run' thinks that it is an additional argument to itself rather than to the output executable. Is there a flag which can tell 'go run' that this is an argument to executable?

mvaidya@mvaidya-VirtualBox:~/junkeork$ go run readfile.go readfile.go package main: case-insensitive file name collision: "readfile.go" and "readfile.go" mvaidya@mvaidya-VirtualBox:~/junkeork$

错误:

包主文件:不区分大小写的文件名冲突:"readfile.go"和" readfile.go"

package main: case-insensitive file name collision: "readfile.go" and "readfile.go"

推荐答案

您可以使用-将gofiles与参数分开:

You can use -- to separate gofiles from arguments:

go run readfile.go -- readfile.go