如何在Bash脚本退出之前运行命令?

本文介绍了如何在Bash脚本退出之前运行命令?的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！ 问题描述

如果Bash脚本具有set -e，并且脚本中的命令返回错误，那么如何在脚本退出之前进行一些清除?

If a Bash script has set -e, and a command in the script returns an error, how can I do some cleanup before the script exits?

例如:

#!/bin/bash set -e mkdir /tmp/foo # ... do stuff ... rm -r /tmp/foo

即使... do stuff ...中的命令之一失败，我如何确保将/tmp/foo删除?

How can I ensure that /tmp/foo is removed, even if one of the commands in ... do stuff ... fails?

推荐答案

以下是使用陷阱的示例:

Here's an example of using trap:

#!/bin/bash -e function cleanup { echo "Removing /tmp/foo" rm -r /tmp/foo } trap cleanup EXIT mkdir /tmp/foo asdffdsa #Fails

输出:

dbrown@luxury:~ $ sh traptest t: line 9: asdffdsa: command not found Removing /tmp/foo dbrown@luxury:~ $

请注意，即使asdffdsa行失败，清理仍会执行.

Notice that even though the asdffdsa line failed, the cleanup still was executed.