我正在尝试使用以前在dart中定义的变量来访问类值,但我不断收到错误未为该类定义运算符[]
I'm trying to access a class value by using a variable previously defined in dart, but I keep getting the error the operator [] isn't defined for the class
在Java语言中,我将使用如下变量访问对象值:
In Javascript I would access an object value using a variable like this:
let movie = { movieTitle : 'Toy Story', actor: 'Tom Hanks' } let actorName = 'actor'; console.log(movie[actorName]); // <- what I'm trying to replicate in dart // expected output: Tom Hanks这是我尝试过并抛出的错误
Here is what I've tried and is throwing that error
class Movie { String name; String actor; String producer; } void main() { var movieTitle = new Movie(); movieTitle.name = 'Toy Story'; movieTitle.actor = 'Tom Hanks'; print(movieTitle.actor); <- prints out Tom Hanks as expected var actorName = 'actor'; print(movieTitle[actorName]); <- throws error }我希望能够在飞来获取价值。
I expect to be able to use a variable on the fly to access the value.
对我来说,一个微不足道的用例是,如果我有一个电影类列表,其中一些演员和制片人为空,我想过滤两个非空演员或具有以下功能的制作人:
A trivial use case for me would be if I had a a list of Movie classes, where some actors and producers are null, I would like to filter on either non null actors or producer with a function like so:
List values = movieList.where((i) => i.actor != "null").toList(); // returns all Movies in movieList where the actor value isn't the string "null" var actorIsNull = 'actor'; List values = movieList.where((i) => i[actorisNull] != "null").toList(); // throws error推荐答案
包含其名称的字符串。 (带镜子-不在此答案范围内。)
You cannot access class members by a string containing their name. (Except with mirrors - outside the scope of this answer.)
您可以完全删除该类,而只需使用 Map< String,String> 。
You could remove the class altogether and just use a Map<String, String>.
Map<String, String> movie = { 'movieTitle': 'Toy Story', 'actor': 'Tom Hanks', }您可以在类中添加一些 bool 方法。
You could add some bool methods on the class.
bool hasNoActor() => actor == null; ... List values = movieList.where((m) => !m.hasNoActor()).toList();或者,您可以将lambda传递给映射器。
Or, you could pass a lambda to your mapper.
Movie movieTitle = Movie() ..name = 'Toy Story' ..actor = 'Tom Hanks'; Function hasActor = (Movie m) => m.actor != null; List values = movieList.where(hasActor).toList();更多推荐
使用变量作为键访问对象值
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