如何通过点击Swift中的按钮打开fb和instagram应用程序

本文介绍了如何通过点击Swift中的按钮打开fb和instagram应用程序的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！ 问题描述

如何通过点击Swift中的按钮打开Facebook和instagram应用程序？在某些应用程序中，通过点击重定向到Facebook应用程序的东西并打开一些页面。如何在Swift中做同样的事情？

How can I open facebook and instagram app by tapping on button in Swift? In some apps by tapping on something it redirects to the facebook app and opens some page. How can I do the same thing in Swift?

我发现了，

var url = NSURL(string: "itms://itunes.apple/de/app/x-gift/id839686104?mt=8&uo=4") if UIApplication.sharedApplication().canOpenURL(url!) { UIApplication.sharedApplication().openURL(url!) }

但这里我必须知道一个应用程序的URL。其他例子在ObjC中，我根本不知道= /

but here I must to know an app URL. And other examples was in ObjC, which I do not know at all =/

推荐答案

看看这些链接，它可以帮助您：

Take a look on these links, it can help you:

https ：//instagram/developer/mobile-sharing/iphone-hooks/

wiki.akosma/IPhone_URL_Schemes

在iOS上打开Facebook应用程序的Facebook链接

否则有一个Instagram的例子，用于打开特定的个人资料（昵称：johndoe here）：

Otherwise there is a quick example with Instagram for opening a specific profile (nickname : johndoe here) :

var instagramHooks = "instagram://user?username=johndoe" var instagramUrl = NSURL(string: instagramHooks) if UIApplication.sharedApplication().canOpenURL(instagramUrl!) { UIApplication.sharedApplication().openURL(instagramUrl!) } else { //redirect to safari because the user doesn't have Instagram UIApplication.sharedApplication().openURL(NSURL(string: "instagram/")!) }