需要帮助 Discord 机器人队列

本文介绍了需要帮助 Discord 机器人队列的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！ 问题描述

我一直在尝试为不和谐机器人创建队列，而我的 >q 命令基本上可以作为 joinplay queue 同时进行.问题是它只能同时排队 2 首歌曲，所以我需要帮助让它排队多首歌曲

i've been tryin to make a queue for discord bot and my >q command basicaly work as join play queue at the same time. The problem is it only queues 2 songs at the same time so I need help making it queue multi songs

queues = {} #check queue def check_queue(ctx, id): if queues[id] !=[]: voice = ctx.guild.voice_client voice.play(queues[id].pop(0)) #command @clientmand(pass_context = True) async def q(ctx, url): if (ctx.author.voice): channel = ctx.message.author.voice.channel voice = get(client.voice_clients, guild=ctx.guild) if voice and voice.is_connected(): await voice.move_to(channel) else: voice = await channel.connect() else: await ctx.send('You are not in a voice channel') YDL_OPTIONS = {'format': 'bestaudio', 'noplaylist': 'True'} FFMPEG_OPTIONS = {'before_options': '-reconnect 1 -reconnect_streamed 1 -reconnect_delay_max 5', 'options': '-vn'} voice = get(client.voice_clients, guild=ctx.guild) with YoutubeDL(YDL_OPTIONS) as ydl: info = ydl.extract_info(url, download=False) URL = info['url'] source = (FFmpegPCMAudio(URL, **FFMPEG_OPTIONS)) if voice.is_playing(): guild_id = ctx.message.guild.id if guild_id in queues: queues[guild_id].append(source) else: queues[guild_id]=[source] await ctx.send('Deemo: Song added to queue') else: ctx.voice_client.stop() voice.play(FFmpegPCMAudio(URL, **FFMPEG_OPTIONS), after=lambda x=0: check_queue(ctx, ctx.message.guild.id)) voice.is_playing() await ctx.send('Playing: '+ info.get('title'))

推荐答案

经过一番研究和搜索，我想出了一个简单的方法来让队列循环 2+ 首歌曲，添加 after=lambda x=0:check_queue(ctx, ctx.message.guild.id) 在 check_queue 里面稍微改一下，就变成这样了

after I do some study and search I figure out an easy way to make the queue loop 2+ songs, add after=lambda x=0: check_queue(ctx, ctx.message.guild.id) inside check_queue and change a little and it will look like this

def check_queue(ctx, id): if queues[id] !=[]: voice = ctx.guild.voice_client source = queues[id].pop(0) voice.play(source, after=lambda x=0: check_queue(ctx, ctx.message.guild.id))