在Python中使用多个NOT IN语句

本文介绍了在Python中使用多个NOT IN语句的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！ 问题描述

我需要在循环中包含三个特定特定子字符串的URL。以下代码有效，但我确信有更优雅的方法：

I need to URLs with three specific specific substrings out of a loop. The following code worked, but I am sure there's a more elegant way to do it:

for node in soup.findAll('loc'): url = node.text.encode("utf-8") if "/store/" not in url and "/cell-phones/" not in url and "/accessories/" not in url: objlist.loc.append(url) else: continue

谢谢！

推荐答案

url = node.text.encode("utf-8") sub_strings = ['/store','/cell-phones/','accessories'] if not any(x in url for x in sub_strings): objlist.loc.append(url) else: continue

来自 docs ：

任何如果iterable的任何元素为true，则返回True。如果iterable为空，则返回False。相当于：

any returns True if any element of the iterable is true. If the iterable is empty, return False. Equivalent to:

def any(iterable): for element in iterable: if element: return True return False