如何为复杂的 json 文档定义 avro 模式?

编程入门行业动态更新时间:2024-10-26 19:24:52

本文介绍了如何为复杂的 json 文档定义 avro 模式?的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！问题描述

我有一个 JSON 文档，我想将其转换为 Avro，并且需要为此目的指定一个架构.这是我想为其定义 avro 模式的 JSON 文档:

I have a JSON document that I would like to convert to Avro and need a schema to be specified for that purpose. Here is the JSON document for which I would like to define the avro schema:

{ "uid": 29153333, "somefield": "somevalue", "options": [ { "item1_lvl2": "a", "item2_lvl2": [ { "item1_lvl3": "x1", "item2_lvl3": "y1" }, { "item1_lvl3": "x2", "item2_lvl3": "y2" } ] } ] }

我可以为非复杂类型定义架构，但不能为复杂的选项"字段定义架构:

I'm able to define the schema for the non-complex types but not for the complex "options" field:

{ "namespace" : "my.ns", "type" : "record", "fields" : [ {"name": "uid", "type": "int"}, {"name": "somefield", "type": "string"} {"name": "options", "type": .....} ] }

感谢您的帮助！

推荐答案

需要使用Avro 复杂类型，特别是数组和记录.然后将它们嵌套在一起:

You need to use Avro complex types, specifically arrays and records. And then nest these together:

{ "namespace" : "my.ns", "name": "myrecord", "type" : "record", "fields" : [ {"name": "uid", "type": "int"}, {"name": "somefield", "type": "string"}, {"name": "options", "type": { "type": "array", "items": { "type": "record", "name": "lvl2_record", "fields": [ {"name": "item1_lvl2", "type": "string"}, {"name": "item2_lvl2", "type": { "type": "array", "items": { "type": "record", "name": "lvl3_record", "fields": [ {"name": "item1_lvl3", "type": "string"}, {"name": "item2_lvl3", "type": "string"} ] } }} ] } }} ] }