本文介绍了您如何在Ruby中进行多态?的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
在C#中,我可以这样做:
In C#, I can do this:
class Program { static void Main(string[] args) { List<Animal> animals = new List<Animal>(); animals.Add(new Dog()); animals.Add(new Cat()); foreach (Animal a in animals) { Console.WriteLine(a.MakeNoise()); a.Sleep(); } } } public class Animal { public virtual string MakeNoise() { return String.Empty; } public void Sleep() { Console.Writeline(this.GetType().ToString() + " is sleeping."); } } public class Dog : Animal { public override string MakeNoise() { return "Woof!"; } } public class Cat : Animal { public override string MakeNoise() { return "Meow!"; } }很明显,输出是(略有释义):
Obviously, the output is (Slightly paraphrased):
- 编织
- 狗在睡觉
- 喵
- 猫在睡觉
由于C#经常因其冗长的类型语法而被嘲笑,您如何使用诸如Ruby之类的鸭式语言处理多态/虚拟方法?
Since C# is often mocked for its verbose type syntax, how do you handle polymorphism/virtual methods in a duck typed language such as Ruby?
推荐答案为您更新的问题添加了更多代码
edit: added more code for your updated question
免责声明:我已经有大约一年没有使用Ruby了,并且没有在该机器上安装Ruby,因此语法可能完全错误.但是这些概念是正确的.
disclaimer: I haven't used Ruby in a year or so, and don't have it installed on this machine, so the syntax might be entirely wrong. But the concepts are correct.
完全相同的方法,包括类和重写的方法:
The exact same way, with classes and overridden methods:
class Animal def MakeNoise return "" end def Sleep print self.class.name + " is sleeping.\n" end end class Dog < Animal def MakeNoise return "Woof!" end end class Cat < Animal def MakeNoise return "Meow!" end end animals = [Dog.new, Cat.new] animals.each {|a| print a.MakeNoise + "\n" a.Sleep }更多推荐
您如何在Ruby中进行多态?
发布评论