我有一个字符串,我需要扫描每次出现的foo"并读取它后面的所有文本,直到第二个 ".因为 Rust 没有 包含字符串函数,我需要通过字符扫描来迭代它.我该怎么做?
I have a string and I need to scan for every occurrence of "foo" and read all the text following it until a second ". Since Rust does not have a contains function for strings, I need to iterate by characters scanning for it. How would I do this?
编辑:Rust 的 &str 有一个 contains() 和 find() 方法.
Edit: Rust's &str has a contains() and find() method.
推荐答案我需要通过字符扫描来迭代它.
I need to iterate by characters scanning for it.
.chars() 方法返回字符串中字符的迭代器.例如
The .chars() method returns an iterator over characters in a string. e.g.
for c in my_str.chars() { // do something with `c` } for (i, c) in my_str.chars().enumerate() { // do something with character `c` and index `i` }如果你对每个char的字节偏移量感兴趣,可以使用char_indices.
If you are interested in the byte offsets of each char, you can use char_indices.
查看 .peekable(),并使用 peek() 进行查看.之所以这样包装,是因为它支持 UTF-8 代码点,而不是简单的字符向量.
Look into .peekable(), and use peek() for looking ahead. It's wrapped like this because it supports UTF-8 codepoints instead of being a simple vector of characters.
您也可以创建一个 char 向量并从那里开始处理它,但这需要更多的时间和空间:
You could also create a vector of chars and work on it from there, but that's more time and space intensive:
let my_chars: Vec<_> = mystr.chars().collect();更多推荐
你如何逐个字符地遍历一个字符串
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