代码工作,但我仍然有一些错误日志。
线程main中的异常java.lang.IndexOutOfBoundsException:Index:4,Size:4 at java.util.ArrayList。 RangeCheck(ArrayList.java:547)在java.util.ArrayList.get(ArrayList.java:322)在UniqueNames.showUnique(UniqueNames.java:23)在UniqueNames.main (UniqueNames.java:39)为什么 Arraylist ,它可以自己扩展它的容量,仍然得到一个 OutOfBoundsException ?
这是我的完整代码:
import acm.io. *; import acm.program.ConsoleProgram; import acm.util。*; import java.io. *; import java.util.ArrayList; import java.lang。*; public class UniqueNames extends ConsoleProgram { static ArrayList< String> meString = new ArrayList< String>(); static String input; public static void storeUnique(String input){ if(!meString.contains(input)) { meString.add(input); } } public static void showUnique(ArrayList< String> meString){ System.out.println(Unique name list contains:); (int i = 0; i< = meString.size(); i ++){ System.out.println(meString.get(i)); } } public static void main(String [] args){ try { InputStreamReader stream = new InputStreamReader 。在); BufferedReader br = new BufferedReader(stream); while(true){ System.out.println(Enter name:); String input = br.readLine(); if(input.equals())break; storeUnique(input); } {showUnique(meString);} } catch(IOException e){} } }解决方案
以下行:
$ b $对于(int i = 0; i <= meString.size(); i ++){ System.out.println(meString.get)的 $ b (一世)); }应该是:
}这是因为列表的索引从零开始。
索引:4,大小:4 再说一遍。当您调用 get(4)时,会发生异常,因为您的列表的大小为4. get(4)将尝试访问列表中的第5个元素。
您可以访问的有效元素为 get(0), get(1), get(2), get(3) code>。
I'm a general 3D artist, switched from my career and started to learn programming. I've got a problem with c106a handout #5.
The code works, but I've still got some error log here.
Exception in thread "main" java.lang.IndexOutOfBoundsException: Index: 4, Size: 4 at java.util.ArrayList.RangeCheck(ArrayList.java:547) at java.util.ArrayList.get(ArrayList.java:322) at UniqueNames.showUnique(UniqueNames.java:23) at UniqueNames.main(UniqueNames.java:39)Why does Arraylist, which can stretch its capacity on its own, still get an OutOfBoundsException?
Here's my full code:
import acm.io.*; import acm.program.ConsoleProgram; import acm.util.*; import java.io.*; import java.util.ArrayList; import java.lang.*; public class UniqueNames extends ConsoleProgram{ static ArrayList<String> meString = new ArrayList<String>(); static String input ; public static void storeUnique(String input){ if (!meString.contains(input)) { meString.add(input); } } public static void showUnique(ArrayList<String> meString){ System.out.println("Unique name list contains:"); for(int i=0 ;i<= meString.size() ;i++){ System.out.println(meString.get(i)); } } public static void main(String[] args){ try{ InputStreamReader stream = new InputStreamReader(System.in); BufferedReader br = new BufferedReader(stream); while (true){ System.out.println("Enter name:"); String input = br.readLine(); if (input.equals("")) break; storeUnique(input); } {showUnique(meString);} } catch(IOException e){ } } }解决方案
The following lines:
for (int i = 0; i <= meString.size(); i++) { System.out.println(meString.get(i)); }should be:
for (int i = 0; i < meString.size(); i++) { System.out.println(meString.get(i)); }This is because the index of the list starts from zero.
Index: 4, Size: 4 explains a little more. When you call get(4), an exception occurs because your list only has a size of 4. get(4) would attempt to access the 5th element in the list.
Valid elements you can access would be get(0), get(1), get(2), get(3).
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Java Arraylist有java.lang.IndexOutOfBoundsException?
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