条件中的python正则表达式匹配

本文介绍了条件中的python正则表达式匹配的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！ 问题描述

我正在解析文件，我想针对一些复杂的正则表达式检查每一行.像这样

I am parsing file and I want to check each line against a few complicated regexs. Something like this

if re.match(regex1, line): do stuff elif re.match(regex2, line): do other stuff elif re.match(regex3, line): do still more stuff ...

当然，要做这些事情，我需要匹配对象.我只能想到三种可能性，每种可能性都有待改进.

Of course, to do the stuff, I need the match objects. I can only think of three possibilities, each of which leaves something to be desired.

if re.match(regex1, line): m = re.match(regex1, line) do stuff elif re.match(regex2, line): m = re.match(regex2, line) do other stuff ...

这需要进行两次复杂的匹配(这些都是长文件和长正则表达式:/)

which requires doing the complicated matching twice (these are long files and long regex :/)

m = re.match(regex1, line) if m: do stuff else: m = re.match(regex2, line) if m: do other stuff else: ...

随着我越来越缩进，这变得很糟糕.

which gets terrible as I indent further and further.

while True: m = re.match(regex1, line) if m: do stuff break m = re.match(regex2, line) if m: do other stuff break ...

看起来很奇怪.

什么是正确的方法?

推荐答案

您可以为每个正则表达式所需的操作定义一个函数，并执行类似的操作

You could define a function for the action required by each regex and do something like

def dostuff(): stuff def dootherstuff(): otherstuff def doevenmorestuff(): evenmorestuff actions = ((regex1, dostuff), (regex2, dootherstuff), (regex3, doevenmorestuff)) for regex, action in actions: m = re.match(regex, line) if m: action() break