调用 datetime.datetime.time()方法在 datetime 对象上,并将其与 datetime.time()对象进行比较: p>
如果dt.time() datetime.time(12):或只看 datetime.datetime.hour 属性:
如果dt.hour< 12后者更简单,前者为您提供了更多的灵活性,与包括分钟分量:
如果dt.time()< datetime.time(12,30)演示:
>>> import datetime >>>> dt = datetime.datetime.now()>>> dt datetime.datetime(2014,2,10,10,39,30,768979)>>> dt.time()< datetime.time(12) True >>> dt.hour 12 True >>> dt = dt.replace(hour = 20)>>> dt datetime.datetime(2014,2,10,20,39,30,768979)>>> dt.time()< datetime.time(12) False >>> dt.hour datetime.hour False
I have a datetime object in python and I would like create a function to check whether the input is in the morning or afternoon on the day of the datetime (ie, before or after 12pm). How to I manually create the time 12:00 and can I use greater than or lesser than symbols for this (<, >)?
解决方案Call the datetime.datetime.time() method on the datetime object and compare it with a datetime.time() object:
if dt.time() < datetime.time(12):or just look at the datetime.datetime.hour attribute:
if dt.hour < 12The latter is simpler, the former gives you more flexibility to compare against times that include a minute component:
if dt.time() < datetime.time(12, 30)Demo:
>>> import datetime >>> dt = datetime.datetime.now() >>> dt datetime.datetime(2014, 2, 10, 10, 39, 30, 768979) >>> dt.time() < datetime.time(12) True >>> dt.hour < 12 True >>> dt = dt.replace(hour=20) >>> dt datetime.datetime(2014, 2, 10, 20, 39, 30, 768979) >>> dt.time() < datetime.time(12) False >>> dt.hour < datetime.hour False
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