请检查以下语法并更正它有4个错误

本文介绍了请检查以下语法并更正它有4个错误的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！ 问题描述

main() { char *name; int length; char *cptr = name; name = "DELHI"; printf {"%s\n", name}; while{*cptr != '\0'} { printf{"%C is stored at address %u\n", *cptr, cptr}; cptr++; } length = cptr - name; printf{"\nLength of the string = %d\n", length}; }

推荐答案

为你固定。 Fixed for you. #include <stdio.h> int main() { char *name; name = "DELHI"; int length; char *cptr = name; printf ("%s\n", name); while(*cptr != '\0') { printf("%C is stored at address %p\n", *cptr, cptr); cptr++; } length = cptr - name; printf("\nLength of the string = %d\n", length); return 0; }

顺便说一句，你真的很喜欢花括号，不是吗？

By the way, you really like curly braces, don't you?

你系统地错放了{和} 第7行：printf {％s \ n，name}; - > printf（％s \ n，姓名）; 第8行：while {* cptr！='\ 0'} - > while（* cptr！='\ 0'） 第10行：printf {％C存储在地址％u \ n，* cptr，cptr}; - > printf（％C存储在地址％u \ n，* cptr，cptr）; 第14行：printf {\\\Length of the string =％d \ n，length}; - > printf（字符串的\\\Length =％d \ n，长度）; You systematically misplaced "{" and "}" Line 7: printf {"%s\n", name}; -> printf ("%s\n", name); Line 8: while{*cptr != '\0'} -> while(*cptr != '\0') Line 10: printf{"%C is stored at address %u\n", *cptr, cptr}; -> printf("%C is stored at address %u\n", *cptr, cptr); Line 14: printf{"\nLength of the string = %d\n", length}; -> printf("\nLength of the string = %d\n", length);