如何在锚点上有条件地使用[href]或[routerLink]?

本文介绍了如何在锚点上有条件地使用[href]或[routerLink]?的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！ 问题描述

我需要在本地或外部资源中有条件地指向同一锚链接.我尝试过

I need for the same anchor link to be pointed conditionally locally or to external resource. I tried

<a [href]="outside?externalUrl:null" [routerLink]="outside?[]:['/route',id]" >test</a>

但是它不起作用.我没有收到任何错误，但是它指向同一个本地页面，并且忽略了外部URL.有什么想法吗?

But it doesn't work. I don't get any errors, but it points to the same local page and ignores the external URL. Any ideas?

另一种选择是构造链接，但是我找不到任何文档来访问服务内的routerLink

Another option would be to construct the link, but I can't find any docs how to access routerLink inside a service

我知道我可以使用*ngIf克隆整个链接，但我不想这样做，我的链接包含带有很多选项的视频标签

I know I can clone the whole link with *ngIf but I don't want to do it, my link contains a video tag with a buch of options

推荐答案

最简单的方法是使用*ngIf / else:

<ng-container *ngIf="outside; else internalBlock"> <a [href]="externalUrl">External</a> </ng-container> <ng-template #internalBlock> <a [routerLink]="['/route', id]">Internal</a> </ng-template>

EDIT#1 :(丑陋的解决方法)

由于您不想使用*ngIf(我仍然不明白为什么)，您可以执行以下操作:

Since you don't want to use *ngIf (I still don't understand why), you can do this:

模板:

<a href="javascript:void(0)" (click)="handleClick(outside, '/route', id, externalUrl)">Link</a>

组件:

handleClick(outside: boolean, internalUrl: string, internalId: string, externalUrl: string): void { if (outside) { window.location.href = externalUrl; // You can also use Location class of Angular } else { this.router.navigate([`${internalUrl}/${internalId}`]); } }