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问题描述
我正在尝试将一个 timedelta 对象与另一个对象相除,以计算服务器正常运行时间:
I'm trying to divide one timedelta object with another to calculate a server uptime:
>>> import datetime >>> installation_date=datetime.datetime(2010,8,01) >>> down_time=datetime.timedelta(seconds=1400) >>> server_life_period=datetime.datetime.now()-installation_date >>> down_time_percentage=down_time/server_life_period Traceback (most recent call last): File "<stdin>", line 1, in <module> TypeError: unsupported operand type(s) for /: 'datetime.timedelta' and 'datetime.timedelta'我知道这个已在Python 3.2中解决,但是有
谢谢,
亚当
推荐答案在python≥2.7中,有一种 .total_seconds()方法来计算总数timedelta中包含的秒数:
In Python ≥2.7, there is a .total_seconds() method to compute the total seconds contained in the timedelta:
>>> down_time.total_seconds() / server_life_period.total_seconds() 0.0003779903727652387否则,没有而是计算总的微秒数(对于版本 <2.7 )
Otherwise, there is no way but to compute the total microseconds (for versions < 2.7)
>>> def get_total_seconds(td): return (td.microseconds + (td.seconds + td.days * 24 * 3600) * 1e6) / 1e6 ... >>> get_total_seconds(down_time) / get_total_seconds(server_life_period) 0.0003779903727652387更多推荐
Python 2.6.5:用timedelta划分timedelta
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