我正在使用JSF中的曲棍球URL重写.
I'm using tuckey URL rewriting with JSF.
我想获得包括用户看到的参数在内的相对URL: 例如
I would like to get the relative URL including parameters that the user sees: e.g.
example/mypage?param=test如果我这样做的话
#{view.viewId}我知道
mypage.xhtml
mypage.xhtml
我想得到的是:
mypage?param = test
mypage?param=test
推荐答案
UIViewRoot#getViewId() 返回JSF视图ID.您需要使用 HttpServletRequest#getRequestURI() 获取当前请求URI和 HttpServletRequest#getQueryString() 获取当前请求查询字符串.
The UIViewRoot#getViewId() returns the JSF view ID. You need to use HttpServletRequest#getRequestURI() to obtain the current request URI and HttpServletRequest#getQueryString() to obtain the current request query string.
#{request.requestURI}#{empty request.queryString ? '' : '?'}#{request.queryString}或者,如果是转发的请求,则将其作为以 RequestDispatcher.FORWARD_REQUEST_URI 和 RequestDispatcher.FORWARD_QUERY_STRING :
Or, if it's a forwarded request, get it as a request attribute keyed with RequestDispatcher.FORWARD_REQUEST_URI and RequestDispatcher.FORWARD_QUERY_STRING respectively:
#{requestScope['javax.servlet.forward.request_uri']}#{empty requestScope['javax.servlet.forward.query_string'] ? '' : '?'}#{requestScope['javax.servlet.forward.query_string']}笨拙的是.考虑隐藏在主模板或工具标签/功能的<c:set>中.
Clumsy yes. Consider hiding away in <c:set> of a master template, or an utility tag/function.
更多推荐
使用查询字符串获取重写的URL
发布评论