另一份算法

本文介绍了另一份算法的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！ 问题描述

我有两个向量。

vector<Object> objects; vector<string> names;

这两个向量填充并具有相同的尺寸。我需要一些算法不分配给对象变量。这可能是使用boost ::拉姆达。比方说：

These two vectors are populated and have the same size. I need some algorithm which does assignment to the object variable. It could be using boost::lambda. Let's say:

some_algoritm(objects.begin(), objects.end(), names.begin(), bind(&Object::Name, _1) = _2);

任何建议？

推荐答案

我想不出一个的std :: 算法这一点。但是，你总是可以编写自己的：

I can't think of a std:: algorithm for this. But, you can always write your own:

template < class It1, class It2, class Operator > It2 zip_for_each ( It1 first1, It1 last1, It2 result, Operator op ) { while (first1 != last1) op(*first++, *result++); return result; }

---

修改：另一种选择，如果你能够定义运算符= 适当，是的std ::复制：

---

EDIT: Another alternative, if you are able to define operator= appropriately, is std::copy:

#include <vector> #include <string> struct Object { std::string name; int i; void operator=(const std::string& str) { name = str; } }; int main () { std::vector<Object> objects(3); std::vector<std::string> names(3); names[0] = "Able"; names[1] = "Baker"; names[2] = "Charlie"; std::copy(names.begin(), names.end(), objects.begin()); }