为什么我定义的功能似乎无法运行

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运行时，我无法输入任何内容，并且程序只是结束并什么也不返回，尽管在我的代码中我想输入和输出某些内容.然后我尝试调试，在我定义的函数中设置了许多关键点，但直接转到代码的末尾.我定义的函数似乎无法运行.我对此感到困惑.你能告诉我出什么事了吗?先感谢您.

When run, I cannot input anything and the program just end and return nothing, though in my code I want to input and output something. And then I tried to debug, I set a lot of key points in the function that I defined, but it directly goes to the end of the code. It seems that the function I defined can't be run. I am confused about that. Could you tell me what was wrong? Thank you in advance.

#include<stdio.h> void day_of_year(); int main() { day_of_year; return 0; } void day_of_year() { int year; int month; int day; scanf_s("%d %d %d", &year, &month, &day); int day_tab[2][13] = { {0,31,28,31,30,31,30,31,31,30,31,30,31}, {0,31,29,31,30,31,30,31,31,30,31,30,31} }; int flag, j; flag = (year % 400 == 0) || ((year % 100 != 0) && (year % 4) == 0); for (j = 1; j < month; j++) day += day_tab[flag][j]; printf("%d", day); }

推荐答案

要调用该函数，您的语句应显示为day_of_year();，并带有括号.

To call the function, your statement should read day_of_year();, with the parentheses.

day_of_year;是不带括号的表达式，它评估函数的地址，然后对该函数不执行任何操作.

Without the parentheses, day_of_year; is an expression that evaluates the address of the function, then doesn't do anything with it.