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问题描述
嗨我正在尝试使用单例类的xmpp连接，但是一个方法和一个变量（isxmppsuccess）显示错误。我的文本框也会抛出错误！ 如何在下一页中维护连接？ i是单身人士的新手下面提到的是我的完整代码，第二个是错误行： 我的完整代码：
使用系统; 使用 System.Collections.Generic; 使用 System.Linq; 使用 System.Net; 使用 System.Windows; 使用 System.Windows.Controls; 使用 System.Windows.Navigation; 使用 Microsoft.Phone.Controls; 使用 Microsoft.Phone.Shell; 使用 WP8Xmpp.Resources; 使用 System.Net.XMPP; 使用 System.Threading; 命名空间 WP8Xmpp { public partial class MainPage：PhoneApplicationPage { public MainPage（） { InitializeComponent（）; } private static XMPPClient ObjXmppClient; public class singleton { private static 单例实例; private static XMPPConnection ObjXmppCon; private 布尔 IsXmppSuccess {获得; set ; } public 字符串用户名{获得; set ; } public 字符串密码{获得; set ; } private readonly String Server = taurus; private readonly 字符串 ServerIPAddress = 127.0.0.1:9090; // 127.0.0.1:9090 / 私有 singleton（） { } public static singleton GetInstance（） { if （ instance == null ） { instance = new singleton （）; } return instance; } public static void IsXmppValid（ string UserName， string PassWord） { ObjXmppClient = new XMPPClient（）; ObjXmppClient.JID = UserName + @ + instance.Server; ObjXmppClient.Password = PassWord; ObjXmppClient.Server = instance.ServerIPAddress; // 模拟器的用户服务器和设备的IP地址。 ObjXmppClient.AutoReconnect = 真; ObjXmppClient.RetrieveRoster = true ; ObjXmppClient.PresenceStatus = new PresenceStatus（）{PresenceType = PresenceType.available，IsOnline = true }; ObjXmppClient.AutoAcceptPresenceSubscribe = true ; ObjXmppClient.AttemptReconnectOnBadPing = true ; ObjXmppCon = new XMPPConnection（ObjXmppClient）; ObjXmppCon.Connect（）; ObjXmppClient.Connect（）; // 初始化xmpp连接 ObjXmppCon.OnAsyncConnectFinished + = instance.ObjXmppCon_OnAsyncConnectFinished ; ObjXmppClient.OnStateChanged + = new EventHandler（instance.XMPPClient_OnStateChanged）; Thread.Sleep（ 2000 ）; } public void ObjXmppCon_OnAsyncConnectFinished（xmedianet.socketserver.SocketClient客户端， bool bSuccess， string strErrors） { IsXmppSuccess = client.Connected; } public void XMPPClient_OnStateChanged（ object sender，EventArgs e） // 错误 { 开关（ObjXmppClient.XMPPState） { case XMPPState.Ready： if （IsXmppSucces） // 错误 { 此 .Dispatcher.BeginInvoke （（）= > { // CloseOverLay（）; // MessageBox.Show（成功登录）; NavigationService .Navigate（（ new Uri（ / Output.xaml ？key = success，UriKind.Relative）））; // 错误 // return; }）; } 其他 { 此 .Dispatcher.BeginInvoke（（）= > // 错误 { MessageBox.Show（ 检查服务器名称/ IpAddress ）; return ; }）; } break ; case XMPPState.AuthenticationFailed： this .Dispatcher.BeginInvoke（（）= > // 错误 { MessageBox.Show（ 输入有效的用户名和密码）; return ; }）; break ; } } private void btnLogin_Click（ object sender，RoutedEventArgs e） // 错误 { if （ txtUserName.Text.Trim（）== string .Empty） // 错误 { MessageBox.Show（ 输入用户名）; return ; } if （txtPassword.Password.Trim（）== string 。空） { MessageBox.Show（ 输入密码）; return ; } UserName = txtUserName.Text.Trim（）; PassWord = txtPassword.Password.Trim（）; IsXmppValid（）; } } } }2>我在这些方法中遇到错误：
public void XMPPClient_OnStateChanged（ object sender，EventArgs e） // 错误 { 开关（ObjXmppClient.XMPPState） { case XMPPState.Ready： if （IsXmppSucces） // 不存在错误 { this .Dispatcher.BeginInvoke（（）= > // < pre> Dispatcher - 不包含定义错误 { // CloseOverLay（）; // MessageBox.Show（& quot;成功登录& quot;）; NavigationService.Navigate （（ new Uri（& quot; /Output.xaml？key = success& quot;，UriKind.Relative）））; // 错误 // 返回; }）; } 其他 { 此 .Dispatcher.BeginInvoke（（）=& gt; // 错误 { MessageBox.Show（& quot; Check server name / IpAddress& quot;）; return ; }）; } break ; case XMPPState.AuthenticationFailed： this .Dispatcher.BeginInvoke（（）= & gt; // 错误 { MessageBox.Show（& 输入有效的用户名和密码& quot;）; return ; }）; break ; } } < / pre >2. private void btnLogin_Click（object sender，RoutedEventArgs e）//错误 { if（txtUserName.Text.Trim（）== string.Empty）//无法访问非静态成员 { MessageBox.Show（输入用户名）; 返回; } if（txtPassword.Password.Trim（） == string.Empty） { MessageBox.Show（输入密码）; 返回; } UserName = txtUserName.Text.Trim（）; PassWord = txtP assword.Password.Trim（）; IsXmppValid（）; // 0参数错误 }
解决方案所以有几件事。你的单身人士不是线程安全的，并且可以按照现在的方式进行比赛。关于它的文章非常好： csharpindepth/Articles/General/Singleton.aspx 最简单修复是将实例属性更改为： private 静态懒惰< singleton> instance = new Lazy< singleton>（（）= > new singleton（））; public static singleton GetInstance { get { return instance.Value;现在，您所看到的问题与将事件传递给调用私有变量的其他对象（IsXmppSuccess）有关。现在，您需要看到的问题是什么？$ / p $ p> 。将该变量公之于众。
Hi iam trying an xmpp connection using singleton class,but a methode and a variable(isxmppsuccess) showing errors.My textboxes also throwing error! how i can maintain the connection in next page also? i am new to the singleton below mentioned is my full code and second one is error lines: my full code:
using System; using System.Collections.Generic; using System.Linq; using System.Net; using System.Windows; using System.Windows.Controls; using System.Windows.Navigation; using Microsoft.Phone.Controls; using Microsoft.Phone.Shell; using WP8Xmpp.Resources; using System.Net.XMPP; using System.Threading; namespace WP8Xmpp { public partial class MainPage : PhoneApplicationPage { public MainPage() { InitializeComponent(); } private static XMPPClient ObjXmppClient; public class singleton { private static singleton instance; private static XMPPConnection ObjXmppCon; private Boolean IsXmppSuccess { get; set; } public String UserName { get; set; } public String PassWord { get; set; } private readonly String Server = "taurus"; private readonly String ServerIPAddress = "127.0.0.1:9090";//127.0.0.1:9090/ private singleton() { } public static singleton GetInstance() { if (instance == null) { instance = new singleton(); } return instance; } public static void IsXmppValid(string UserName, string PassWord) { ObjXmppClient = new XMPPClient(); ObjXmppClient.JID = UserName + "@" + instance.Server; ObjXmppClient.Password = PassWord; ObjXmppClient.Server = instance.ServerIPAddress; //user server for emulator and ip address for device. ObjXmppClient.AutoReconnect = true; ObjXmppClient.RetrieveRoster = true; ObjXmppClient.PresenceStatus = new PresenceStatus() { PresenceType = PresenceType.available, IsOnline = true }; ObjXmppClient.AutoAcceptPresenceSubscribe = true; ObjXmppClient.AttemptReconnectOnBadPing = true; ObjXmppCon = new XMPPConnection(ObjXmppClient); ObjXmppCon.Connect(); ObjXmppClient.Connect(); //initializing the xmpp connection ObjXmppCon.OnAsyncConnectFinished +=instance.ObjXmppCon_OnAsyncConnectFinished; ObjXmppClient.OnStateChanged += new EventHandler(instance.XMPPClient_OnStateChanged); Thread.Sleep(2000); } public void ObjXmppCon_OnAsyncConnectFinished(xmedianet.socketserver.SocketClient client, bool bSuccess, string strErrors) { IsXmppSuccess = client.Connected; } public void XMPPClient_OnStateChanged(object sender, EventArgs e)//error { switch (ObjXmppClient.XMPPState) { case XMPPState.Ready: if (IsXmppSucces)//error { this.Dispatcher.BeginInvoke(() => { //CloseOverLay(); //MessageBox.Show("Successfully logged in"); NavigationService.Navigate((new Uri("/Output.xaml?key=success", UriKind.Relative)));//error //return; }); } else { this.Dispatcher.BeginInvoke(() =>//error { MessageBox.Show("Check server name/IpAddress"); return; }); } break; case XMPPState.AuthenticationFailed: this.Dispatcher.BeginInvoke(() =>//error { MessageBox.Show("Enter valid username and password"); return; }); break; } } private void btnLogin_Click(object sender, RoutedEventArgs e)//error { if (txtUserName.Text.Trim() == string.Empty)//error { MessageBox.Show("Enter Username"); return; } if (txtPassword.Password.Trim() == string.Empty) { MessageBox.Show("Enter Password"); return; } UserName = txtUserName.Text.Trim(); PassWord = txtPassword.Password.Trim(); IsXmppValid(); } } } }2> i am getting error in these methodes:
public void XMPPClient_OnStateChanged(object sender, EventArgs e)//error { switch (ObjXmppClient.XMPPState) { case XMPPState.Ready: if (IsXmppSucces) // doesnot exist error { this.Dispatcher.BeginInvoke(() =>//<pre>Dispatcher-doesnot contain the definition error { //CloseOverLay(); //MessageBox.Show("Successfully logged in"); NavigationService.Navigate((new Uri("/Output.xaml?key=success", UriKind.Relative)));//error //return; }); } else { this.Dispatcher.BeginInvoke(() =>//error { MessageBox.Show("Check server name/IpAddress"); return; }); } break; case XMPPState.AuthenticationFailed: this.Dispatcher.BeginInvoke(() =>//error { MessageBox.Show("Enter valid username and password"); return; }); break; } } </pre>2. private void btnLogin_Click(object sender, RoutedEventArgs e)//error { if (txtUserName.Text.Trim() == string.Empty)//cannot access non static member { MessageBox.Show("Enter Username"); return; } if (txtPassword.Password.Trim() == string.Empty) { MessageBox.Show("Enter Password"); return; } UserName = txtUserName.Text.Trim(); PassWord = txtPassword.Password.Trim(); IsXmppValid();//0 arguments error }
解决方案 So a couple of things. Your singleton isn't thread safe, and could race with the way it's implemented now. There is an excellent article about it at: csharpindepth/Articles/General/Singleton.aspx The easiest fix is to change the instance property to: private static Lazy<singleton> instance = new Lazy<singleton>(() => new singleton()); public static singleton GetInstance { get { return instance.Value; } }Now, the issue that you're seeing is related to passing events to other objects that call a private variable (IsXmppSuccess). Make that variable public.
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单例类抛出名称不存在,错误
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