Scala中的apply方法是什么，尤其是在类型定义中使用的方法

本文介绍了Scala中的apply方法是什么，尤其是在类型定义中使用的方法的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！ 问题描述

我知道apply方法在伴侣对象中使用时是语法糖. 但是，在类型定义中使用apply方法的方式如下所示?

I know that apply method is syntactic sugar when used in companion object. However, what is apply method for when it is used in type definition just like below?

type Applyn = { def apply[A](f: A=>A, n: Int, x: A): A }

这句话之间有区别吗? 我猜想这句话是用来为Applyn分配泛型函数值的.

Is there a deference between this sentence? As I guess, this sentence is used for assigning generic function value to Applyn.

例如，通过使用上面的句子，我们可以制作

For example, by using above sentence, we can make

(Int=>Int, Int, Int)=>Int

(String=>String, Int, String)=>String

等，仅转换为单一类型Applyn.

etc., into only a single type Applyn.

这正确吗?

推荐答案

您正在寻找的是结构类型.它不引用任何特定类型，而是引用具有方法apply[A](f: A=>A, n: Int, x: A): A的任何类型.函数具有apply方法，因此具有正确签名的函数也适用，但是也可以创建具有非函数的apply方法的类型.想象一下.

What you are looking is a structural type. It doesn't refer to any specific type but any type that has a method apply[A](f: A=>A, n: Int, x: A): A. Functions have an apply method, so a function with the correct signature applies, but it's also possible to create types that have that apply method that are not functions. Imagine the following.

object NotAFunction { def apply[A](f: A=>A, n: Int, x: A): A = {...} }

该对象没有扩展Function，因此它不是函数，但仍满足结构类型要求.

This object doesn't extend Function, so it is not a function but it still satisfies the structural type requirement.

结构类型提供了不错的语法，但是它们的速度非常慢，因此应尽可能避免使用它们，特别是在性能关键的代码中.

Structural types provide a nice syntax but they are very slow, so they should be avoided where possible, especially in performance critical code.