如何避免儿童重复构造函数

本文介绍了如何避免儿童重复构造函数的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！ 问题描述

我有一个父类，其构造函数为：

I have a parent class, which has constructor as:

@Inject public AbstractResource(@Named("authorization") Authorization auth, @Named("helper") Helper helper) { this.authorization = authorization; this.helper = helper; }

现在在children类中，我有类似的构造函数：

now in the children class, i have similar constructor:

public class MyResource extends AbstractResource { private Manager manager; @Inject public MyResource(@Named("authorization") Authorization auth, @Named("helper") Helper helper) { super(auth, helper); this.manager = new Manager(); } ...

问题是我有很多孩子上课了吗来自AbstractResource，我必须再次使用'Authorization'和'Helper'编写类似的构造函数。有什么办法可以避免重复编码？

Problem is I have tons of children class extend from AbstractResource, I have to write the similar constructor with 'Authorization' and 'Helper' again and agin. is there any way i can avoid the repetitive coding?

对不起，更新了我的代码，是的，我可以在每个子类中调用super（..），但是仍然在每个构造函数中我都注入了所有这些参数，auth和帮助者，只是想知道是否有一种方法可以简化该过程

Sorry, updated my code, yes, i can call super(..) in each children class, but still in each constructor i have inject all those parameters, auth and helper, just wonder if there is a way to even simplify that

推荐答案

除非我对此有所遗漏，否则有一个简单的方法

Unless I'm missing something about this there is a simple solution by calling through to the parent's constructor.

在子类的构造函数中，第一行应为： super（authorization，helper）

In your child class's constructor the first line should be: super(authorization, helper)

编辑：作者已编辑了问题，因此该解决方案不再适用。

Author has edited his question so this solution is no longer applicable.