将应用程序传递给AndroidViewModel

本文介绍了将应用程序传递给AndroidViewModel的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！ 问题描述

我想在我的视图中使用 AndroidViewModel 模型以访问Context.它要求Application作为参数传递.我的ViewModel类如下:

I would like to use AndroidViewModel for my view model in order to get access to the Context. It requires Application to be passed as a parameter. My ViewModel class looks like this:

class FooAndroidViewModel(application: Application?) : AndroidViewModel(aplication) { ... }

它正像这样被实例化:

val fooModel = ViewModelProviders.of(this).get(FooAndroidViewModel::class.java)

问题在于这会产生错误，无法实例化FooAndroidViewModel-可能是由于缺少application参数所致.

The problem is that this gives an error, that FooAndroidViewModel cannot be instantiated - probably because of the missing application parameter.

问题:如何将application传递给ViewModelProviders.of(this).get(FooAndroidViewModel::class.java)?

推荐答案

只需将application: Application?替换为application: Application.

以下代码应该可以工作:

Following code should work:

class FooAndroidViewModel(application: Application) : AndroidViewModel(aplication) { ... }