xlua游戏热更新(C#访问lua)

游戏热更新(C#访问lua)"/>

xlua游戏热更新(C#访问lua)

xlua作为Unity资源热更新的重要解决方案api，在Tecent重多游戏中被采用，本文通过案例去讲解xlua代码结构层次。

/** Tencent is pleased to support the open source community by making xLua available.* Copyright (C) 2016 THL A29 Limited, a Tencent company. All rights reserved.* Licensed under the MIT License (the "License"); you may not use this file except in compliance with the License. You may obtain a copy of the License at* * Unless required by applicable law or agreed to in writing, software distributed under the License is distributed on an "AS IS" BASIS, WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied. See the License for the specific language governing permissions and limitations under the License.
*/using UnityEngine;
using XLua;namespace XLuaTest
{public class Helloworld : MonoBehaviour{// Use this for initializationvoid Start(){//创建xlua虚拟机LuaEnv luaenv = new LuaEnv();luaenv.DoString("print('hello xlua!')");luaenv.DoString("CS.UnityEngine.Debug.Log('hello world')");//释放资源luaenv.Dispose();}// Update is called once per frame}
}

加载lua文件

Resources.Load(“xlua/xx.lua”) 加载

创建Resources 目录下xx.lua.txt文件

//创建xlua虚拟机【建议全局唯一】
LuaEnv luaenv = new LuaEnv();
//加载lua脚本资源
TextAsset textAsset = Resources.Load<TextAsset>("xlua/hello.lua");
luaenv.DoString(textAsset.ToString());

loader加载

luaenv.DoString("require 'xlua/hello'"); //require + 'lua文件名称不加扩展名'
//require 实际上是逐个查找loader文件 是否存在指定文件

自定义loader

挨个查找loader，若某个loader返回了字节数组，那么便不继续查找了

  //加载loaderluaenv.AddLoader(Myloader);luaenv.DoString("require 'xlua/hello'");//挨个查找loader，若某个loader返回了字节数组，那么便不继续查找了//释放资源luaenv.Dispose();/// <summary>/// 自定义loader/// </summary>/// <param name="filePath"></param>/// <returns></returns>private byte[] Myloader(ref string filePath){print(filePath);string s = "print(123)";return Encoding.UTF8.GetBytes(s);}

构建Assets/StreamingAssets文件夹

  private byte[] Myloader(ref string filePath){//print(filePath);string absPath = Application.streamingAssetsPath + "/" + filePath + ".lua.txt";return Encoding.UTF8.GetBytes(File.ReadAllText(absPath));}

C#访问lua文件

全局变量

加载文件成功后，访问lua文件中的全局变量
–number 可以对应int float double

           //通过luaenv 访问变量int integer_Lua = luaenv.Global.Get<int>("Integer");string name_Lua = luaenv.Global.Get<string>("Name");Debug.Log(integer_Lua + name_Lua);

类

//lua文件中person = {Name = "James",Sno = 23,eat = function()print("i'm eating!")end}
//
//C#
class Person{public string _name;public int _sno;}Person luaPerson = luaenv.Global.Get<Person>("person");print(luaPerson._sno + ":" + luaPerson._name);

接口

IPerson luaPerson = luaenv.Global.Get<IPerson>("person");print(luaPerson.sno + ":" + luaPerson.name);[CSharpCallLua]interface IPerson{string name { get; set; }int sno { get; set; }void eat();}

字典

dic = {china = 1,america = 2,uk  = 3,
}

 //通过字典遍历Dictionary<string,int> dic =  luaenv.Global.Get<Dictionary<string, int>>("dic");foreach (var key in dic.Keys){print(key + ":" + dic[key]);}

列表

list = {'sdahjk',12,123,'12'}

  //通过list访问List<object> list =  luaenv.Global.Get<List<object>>("list");foreach (var target in list){print(target.ToString());}

再将上述数据通过List读取一次

LuaTable

LuaTable table = luaenv.Global.Get<LuaTable>("person");table.Get<string>("name");

函数

 [CSharpCallLua]delegate int Add(int a, int b);//函数Add add = luaenv.Global.Get<Add>("add");print(add(3,5));add = null;

lua多返回值通过，out 变量接受

add = function(a,b)return a + b,a,b
end

 delegate int Add2(int a, int b, out int resa, out int resb);

使用LuaFunction （性能差）

LuaFunction add = luaenv.Global.Get<LuaFunction>("add");object[] objects = add.Call(3, 5);print(objects[0]);