如何在Django中动态组成OR查询过滤器?

本文介绍了如何在Django中动态组成OR查询过滤器?的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！ 问题描述

从示例中，您可以看到多个OR查询过滤器:

From an example you can see a multiple OR query filter:

Article.objects.filter(Q(pk=1) | Q(pk=2) | Q(pk=3))

例如，结果为:

[<Article: Hello>, <Article: Goodbye>, <Article: Hello and goodbye>]

但是，我想从列表中创建此查询过滤器.该怎么做?

However, I want to create this query filter from a list. How to do that?

例如[1, 2, 3] -> Article.objects.filter(Q(pk=1) | Q(pk=2) | Q(pk=3))

推荐答案

您可以按以下方式链接查询:

You could chain your queries as follows:

values = [1,2,3] # Turn list of values into list of Q objects queries = [Q(pk=value) for value in values] # Take one Q object from the list query = queries.pop() # Or the Q object with the ones remaining in the list for item in queries: query |= item # Query the model Article.objects.filter(query)