本文介绍了Minimongo目前尚不支持$运算符的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我有这份文件:
... "username" : "torayeff", "profile" : { ... "friends" : [ { "_id" : "aSD4wmMEsFnYLcvmP", "state" : "active" }, { "_id" : "ShFTXxuQLAxWCh4cq", "state" : "active" }, { "_id" : "EQjoKMNBey7WPGamC", "state" : "new-request" } ] ... } ...这是仅获取给定用户的州" 属性的查询:
This is query for getting only "state" attribute of given user:
Meteor.users.findOne({_id: userId1, 'profile.friends._id': userId2}, {fields: {_id: 0, 'profile.friends.state.$':1} });在流星中,我收到此错误:
In meteor I am receiving this error:
Exception while simulating the effect of invoking 'activateFriendship' Error: Minimongo doesn't support $ operator in projections yet...如何在minimongo中没有错误的情况下重写以上查询?
How can I rewrite above query without having error in minimongo?
推荐答案您可以喜欢
如果您只想获取没有键的值,请使用此
EDIT : if you just want to grab the values without keys, use this
Meteor.users.distinct('profile.friends.state', {_id: userId1, 'profile.friends._id': userId2});通常情况下:
Meteor.users.findOne({_id: userId1, 'profile.friends._id': userId2}).select({ _id: 0, 'profile.friends.state':1 }).exec()$不需要项目运营商
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Minimongo目前尚不支持$运算符
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