我有 3 个任务:
private async Task<Cat> FeedCat() {} private async Task<House> SellHouse() {} private async Task<Tesla> BuyCar() {}在我的代码可以继续之前,它们都需要运行,我也需要每个的结果.结果没有任何共同点
They all need to run before my code can continue and I need the results from each as well. None of the results have anything in common with each other
如何调用并等待 3 个任务完成然后获取结果?
How do I call and await for the 3 tasks to complete and then get the results?
推荐答案使用 WhenAll 后,可以使用 await 单独拉出结果:
After you use WhenAll, you can pull the results out individually with await:
var catTask = FeedCat(); var houseTask = SellHouse(); var carTask = BuyCar(); await Task.WhenAll(catTask, houseTask, carTask); var cat = await catTask; var house = await houseTask; var car = await carTask;您也可以使用 Task.Result(因为您知道此时它们都已成功完成).但是,我建议使用 await 因为它显然是正确的,而 Result 在其他情况下可能会导致问题.
You can also use Task.Result (since you know by this point they have all completed successfully). However, I recommend using await because it's clearly correct, while Result can cause problems in other scenarios.
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等待具有不同结果的多个任务
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